Python如何上传本地视频?
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参考代码如下：
from tkinter import *
from tkinter.ttk import *
from tkinter.filedialog import askopenfile
import time
ws = Tk()
ws.title('PythonGuides')
ws.geometry('400x200')
def open_file():
file_path = askopenfile(mode='r', filetypes=[('Vedio Files', '*mp4')])
if file_path is not None:
pass
def uploadFiles():
pb1 = Progressbar(
ws,
orient=HORIZONTAL,
length=300,
mode='determinate'
)
pb1.grid(row=4, columnspan=3, pady=20)
for i in range(5):
ws.update_idletasks()
pb1['value'] += 20
time.sleep(1)
pb1.destroy()
Label(ws, text='File Uploaded Successfully!', foreground='green').grid(row=4, columnspan=3, pady=10)
adhar = Label(
ws,
text='Upload Government id in jpg format '
)
adhar.grid(row=0, column=0, padx=10)
adharbtn = Button(
ws,
text ='Choose File',
command = lambda:open_file()
)
adharbtn.grid(row=0, column=1)
dl = Label(
ws,
text='Upload Driving License in jpg format '
)
dl.grid(row=1, column=0, padx=10)
dlbtn = Button(
ws,
text ='Choose File ',
command = lambda:open_file()
)
dlbtn.grid(row=1, column=1)
ms = Label(
ws,
text='Upload Marksheet in jpg format '
)
ms.grid(row=2, column=0, padx=10)
msbtn = Button(
ws,
text ='Choose File',
command = lambda:open_file()
)
msbtn.grid(row=2, column=1)
upld = Button(
ws,
text='Upload Files',
command=uploadFiles
)
upld.grid(row=3, columnspan=3, pady=10)
ws.mainloop()追问请问不用文件选择框，直接上传该怎么做呢
追答收！费
